Table # 2 The number of dropped arms
The number of intervals K will be equal to the quotient of the division
xmin=6 xmax=15
1 - interval (6+L)=> (6 + 1) = 7 2 - interval (6+2L)=> (6+2) = 8 3 - interval (6+3L)=> (6+3) = 9 4 - interval (6+4L)=> (6+4) = 10 5 - interval (6+5L)=> (6+5) = 11 6 - interval (6 + 6L)=> (6+6) = 12 7 - interval (6+7L)=> (6+7) = 13 8 - interval (6+8L)=> (6+8) = 14 9 - interval (6+9L)=> (6+9) = 15 Table#3
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, 
, then K=9, L=1
