Answer: C.

 

13. What is the value of V_X for the circuit in Fig.5? A. 10V B.5V C.-5V D.-10V E. –15V

Solution:

Let’s consider the node at the center of the circuit.

Current from left branch is I₁=8/2*10³= 4mA.

By KCL: 4+5–10–i_x=0. i_x= –1mA.

V_x=10*10³*(–1*10^-3)= –10V

Answer: D.

 

 

Fig.5

14. What is the value of i_x for the circuit in Fig.5? A. 1mA B.-1mA C.5mA D.-2mA E.2mA

Solution:

Let’s consider the node at the center of the circuit.

Current from left branch is I₁=8/2*10³= 4mA.

By KCL: 4+5–10–i_x=0. i_x= –1mA.

Answer: B.

 

15. What i-v characteristic corresponds to resistor? Picture_____

A.A B.B C.C D.D E.E

A B C D E

 

Solution:

We can see i-v characteristic of resistor from Ohm’s Law: V=IR.

Answer: C.

 

16. What statement is correct?

A. A diode can be used as a voltage divider.

B. Linear element of the circuit is such one whose characteristic is a straight line.

C. Interface between a source and a load is one-port network device.

D. Bilateral element of the circuit is such one whose i-v characteristic curve has odd symmetry about the origin.

E. Bilateral element of the circuit is such one whose i-v characteristic curve has even symmetry about the origin.

 

Solution:

A – wrong. Only resistor and potentiometer can be used as voltage dividers.

B – wrong. Linear means that the defining characteristic is a straight line through the origin. Elements whose characteristics do not pass through the origin (even if it’s a straight line) or are not a straight line are said to be nonlinear.

C – wrong.

D – correct.

E – wrong. Bilateral means that the i-v characteristic curve has odd symmetry about the origin.